## College Physics (4th Edition)

Published by McGraw-Hill Education

# Review & Synthesis: Chapters 6-8 - Review Exercises - Page 323: 1

#### Answer

(a) To measure up to 5.0 kg, the spring needs to stretch a distance of $0.20~m$ (b) The spring constant is $245~N/m$

#### Work Step by Step

(a) The spring stretches 1 mm for every 25 grams. We can find the stretch distance for a mass of $5.0~kg$: $x = \frac{5.0~kg}{0.025~kg/mm} = 0.20~m$ To measure up to 5.0 kg, the spring needs to stretch a distance of $0.20~m$ (b) We can find the spring constant: $kx = mg$ $k = \frac{mg}{x}$ $k = \frac{(5.0~kg)(9.80~m/s^2)}{0.20~m}$ $k = 245~N/m$ The spring constant is $245~N/m$.

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