## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 9 - Problems - Page 361: 16

#### Answer

We can rank the drums in order of the pressure at the bottom of the drum, from largest to smallest: $b = e \gt a = c \gt d$

#### Work Step by Step

We can assume that the atmospheric pressure is the same for all the drums. We can calculate the gauge pressure at the bottom of each drum. (a) $P_g = \rho gh = (1000~kg/m^3)(9.80~m/s^2)(0.80~m) = 7840~Pa$ (b) $P_g = \rho gh = (1000~kg/m^3)(9.80~m/s^2)(1.00~m) = 9800~Pa$ (c) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(1.00~m) = 7840~Pa$ (d) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(0.80~m) = 6272~Pa$ (e) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(1.25~m) = 9800~Pa$ We can rank the drums in order of the pressure at the bottom of the drum, from largest to smallest: $b = e \gt a = c \gt d$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.