#### Answer

We can rank the drums in order of the pressure at the bottom of the drum, from largest to smallest:
$b = e \gt a = c \gt d$

#### Work Step by Step

We can assume that the atmospheric pressure is the same for all the drums. We can calculate the gauge pressure at the bottom of each drum.
(a) $P_g = \rho gh = (1000~kg/m^3)(9.80~m/s^2)(0.80~m) = 7840~Pa$
(b) $P_g = \rho gh = (1000~kg/m^3)(9.80~m/s^2)(1.00~m) = 9800~Pa$
(c) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(1.00~m) = 7840~Pa$
(d) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(0.80~m) = 6272~Pa$
(e) $P_g = \rho gh = (800~kg/m^3)(9.80~m/s^2)(1.25~m) = 9800~Pa$
We can rank the drums in order of the pressure at the bottom of the drum, from largest to smallest:
$b = e \gt a = c \gt d$