## College Physics (4th Edition)

The ratio of the volume of 1.00 kg of platinum to the volume of 1.00 kg of aluminum is $0.126$
We can find an expression for the volume $V_p$ of 1.00 kg of platinum: $V_p = \frac{m}{\rho_p} = \frac{1.00~kg}{21500~kg/m^3}$ We can find an expression for the volume $V_a$ of 1.00 kg of aluminum: $V_a = \frac{m}{\rho_a} = \frac{1.00~kg}{2700~kg/m^3}$ We can find the ratio $\frac{V_p}{V_a}$: $\frac{V_p}{V_a} = \frac{\frac{1.00~kg}{21500~kg/m^3}}{\frac{1.00~kg}{2700~kg/m^3}}$ $\frac{V_p}{V_a} = \frac{2700~kg/m^3}{21500~kg/m^3}$ $\frac{V_p}{V_a} = 0.126$ The ratio of the volume of 1.00 kg of platinum to the volume of 1.00 kg of aluminum is $0.126$.