Answer
The ratio of the volume of 1.00 kg of platinum to the volume of 1.00 kg of aluminum is $0.126$
Work Step by Step
We can find an expression for the volume $V_p$ of 1.00 kg of platinum:
$V_p = \frac{m}{\rho_p} = \frac{1.00~kg}{21500~kg/m^3}$
We can find an expression for the volume $V_a$ of 1.00 kg of aluminum:
$V_a = \frac{m}{\rho_a} = \frac{1.00~kg}{2700~kg/m^3}$
We can find the ratio $\frac{V_p}{V_a}$:
$\frac{V_p}{V_a} = \frac{\frac{1.00~kg}{21500~kg/m^3}}{\frac{1.00~kg}{2700~kg/m^3}}$
$\frac{V_p}{V_a} = \frac{2700~kg/m^3}{21500~kg/m^3}$
$\frac{V_p}{V_a} = 0.126$
The ratio of the volume of 1.00 kg of platinum to the volume of 1.00 kg of aluminum is $0.126$.
