## College Physics (4th Edition)

The pressure on a fish at a depth of 10 meters under the ocean surface is $2.01\times 10^5~Pa$
We can find the pressure at a depth of 10 m under the ocean surface: $P_{abs} = P_{atm}+P_g$ $P_{abs} = P_{atm}+\rho~gh$ $P_{abs} = (1.01\times 10^5~N/m^2)+(1025~kg/m^3)(9.80~m/s^2)(10~m)$ $P_{abs} = 2.01\times 10^5~N/m^2$ The pressure on a fish at a depth of 10 meters under the ocean surface is $2.01\times 10^5~Pa$.