College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 233: 93


The maximum height is 6.1 meters

Work Step by Step

Let $h_2$ be the maximum height. We can use conservation of energy to find the maximum height: $mgh_2 = mgh_1 + \frac{1}{2}mv^2$ $h_2 = h_1 + \frac{v^2}{2g}$ $h_2 = 1.0~m + \frac{(10~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 6.1~m$ The maximum height is 6.1 meters.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.