## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 6 - Problems - Page 233: 93

#### Answer

The maximum height is 6.1 meters

#### Work Step by Step

Let $h_2$ be the maximum height. We can use conservation of energy to find the maximum height: $mgh_2 = mgh_1 + \frac{1}{2}mv^2$ $h_2 = h_1 + \frac{v^2}{2g}$ $h_2 = 1.0~m + \frac{(10~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 6.1~m$ The maximum height is 6.1 meters.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.