## College Physics (4th Edition)

The high jumper needs to be able to sprint at a speed of $4.85~m/s$
We can assume that all the kinetic energy will be converted into gravitational potential energy: $\frac{1}{2}mv^2 = mgh$ $v^2 = 2gh$ $v = \sqrt{2gh}$ $v = \sqrt{(2)(9.80~m/s^2)(1.2~m)}$ $v = 4.85~m/s$ The high jumper needs to be able to sprint at a speed of $4.85~m/s$