College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 233: 102


Tarzan's initial speed should be at least $5.8~m/s$

Work Step by Step

Let $h_1$ be the original height. Let $h_2$ be the height of the higher ground across the gully. We can assume that the final speed is zero. We can use conservation of energy to find the initial speed $v_1$: $mgh_1 + \frac{1}{2}mv_1^2 = mgh_2$ $\frac{1}{2}mv_1^2 = mg~(h_2-h_1)$ $v_1^2 = 2g~(h_2-h_1)$ $v_1 = \sqrt{2g~(h_2-h_1)}$ $v_1 = \sqrt{(2)(9.80~m/s^2)(1.7~m)}$ $v_1 = 5.8~m/s$ Tarzan's initial speed should be at least $5.8~m/s$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.