## College Physics (4th Edition)

$\lambda = 2.43\times 10^{-12}~m$
We can find the wavelength of each photon: $E = \frac{hc}{\lambda}$ $\lambda = \frac{hc}{E}$ $\lambda = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{(511\times 10^3~eV)(1.6\times 10^{-19}~J/eV)}$ $\lambda = 2.43\times 10^{-12}~m$