College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Problems - Page 1043: 48


$K = 11.6~eV$

Work Step by Step

We can find the energy when the atom is in the n=2 state: $E = \frac{E_0}{n^2}$ $E = \frac{-13.6~eV}{2^2}$ $E = -3.4~eV$ The energy required to remove the electron from the atom is $3.4~eV$. We can find the kinetic energy of the electron after it is removed from the atom: $K = 15.0~eV-3.4~eV = 11.6~eV$
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