College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Problems - Page 1043: 59


$\lambda = 7.8\times 10^{-14}~m$

Work Step by Step

We can find the energy of the photon: $E = 8.0~MeV+8.0~MeV$ $E = 16.0~MeV$ We can find the wavelength of the photon: $E = \frac{hc}{\lambda}$ $\lambda = \frac{hc}{E}$ $\lambda = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{(16.0\times 10^6~eV)(1.6\times 10^{-19}~J/eV)}$ $\lambda = 7.8\times 10^{-14}~m$
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