## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 27 - Problems - Page 1042: 38

#### Answer

The smallest energy photon that can be absorbed has an energy of $10.2~eV$

#### Work Step by Step

The smallest energy photon would have the energy to make the electron jump from the ground state to the n=2 state. We can find the energy when the atom is in the n=2 state: $E = \frac{E_0}{n^2}$ $E = \frac{-13.6~eV}{2^2}$ $E = -3.4~eV$ We can find the energy difference between the two states: $\Delta E = E_f-E_i$ $\Delta E = (-3.4~eV)-(-13.6~eV)$ $\Delta E = 10.2~eV$ The smallest energy photon that can be absorbed has an energy of $10.2~eV$.

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