College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Problems - Page 1042: 33


$E = -0.85~eV$

Work Step by Step

We can find the energy of the hydrogen atom in the stationary state $n=4$: $E = \frac{-E_0}{n^2}$ $E = \frac{-13.6~eV}{4^2}$ $E = -0.85~eV$
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