Answer
$f = 1.1\times 10^{19}~Hz$
Work Step by Step
We can find the cut off frequency:
$hf = q~\Delta V$
$f = \frac{q~\Delta V}{h}$
$f = \frac{(1.6\times 10^{-19}~C)(46000~V)}{6.626\times 10^{-34}~J~s}$
$f = 1.1\times 10^{19}~Hz$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 27 - Problems - Page 1042: 18
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