## College Physics (4th Edition)

We can find the distance traveled according to the muon: $L = v~t$ $L = (0.994)(3.0\times 10^8~m/s)(2.2\times 10^{-6}~s)$ $L = 656~m$ We can find the distance $L_0$ traveled in the lab frame: $L = L_0~\sqrt{1-\frac{v^2}{c^2}}$ $L_0 = \frac{L}{\sqrt{1-\frac{v^2}{c^2}}}$ $L_0 = \frac{656~m}{\sqrt{1-\frac{(0.994~c)^2}{c^2}}}$ $L_0 = 6000~m = 6.0~km$ The distance traveled in the lab frame is 6.0 km