## College Physics (4th Edition)

The time difference between the two clocks is $7.92~ns$
Let $\Delta t_0$ be the time measured on the plane. $\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2}}}$ $\Delta t_0 = \Delta t~\sqrt{1-\frac{v^2}{c^2}}$ $\Delta t_0 = (8.0~h)~\sqrt{1-\frac{(220~m/s)^2}{(3.0\times 10^8~m/s)^2}}$ $\Delta t_0 = 7.9999999999978~h$ We can find the time difference: $8.0~h-7.9999999999978~h = 0.0000000000022~h$ $0.0000000000022~h = 7.92~ns$ The time difference between the two clocks is $7.92~ns$.