## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 26 - Problems - Page 1010: 18

#### Answer

The length according to the pilot on the spaceship is $56.0~m$

#### Work Step by Step

Let $L = 40.0~m$ We can find the length $L_0$ measured by the pilot on the spaceship: $L = L_0~\sqrt{1-\frac{v^2}{c^2}}$ $L_0 = \frac{L}{\sqrt{1-\frac{v^2}{c^2}}}$ $L_0 = \frac{40.0~m}{\sqrt{1-\frac{(0.70~c)^2}{c^2}}}$ $L_0 = 56.0~m$ The length according to the pilot on the spaceship is $56.0~m$

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