College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 22 - Problems - Page 865: 56

Answer

The wavelength measured by an observer on the Earth is $864~nm$

Work Step by Step

Let $\lambda_0 = 480~nm$ and let $\lambda'$ be the wavelength measured by an observer on the Earth. We can find the wavelength measured by an observer on the Earth: $\frac{\lambda'-\lambda_0}{\lambda_0} = \frac{v}{c}$ $\lambda'-\lambda_0 = \frac{v}{c}~\lambda_0$ $\lambda' = \frac{v}{c}~\lambda_0+\lambda_0$ $\lambda' = \frac{2.4\times 10^8~m/s}{3.0\times 10^8~m/s}~(480~nm)+(480~nm)$ $\lambda' = 864~nm$ The wavelength measured by an observer on the Earth is $864~nm$.
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