College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 22 - Problems - Page 865: 44

Answer

The fraction of the incident light intensity that is transmitted is $\frac{1}{4}$

Work Step by Step

Since the light is unpolarized initially, the intensity of the light after passing through the first polarizer is $\frac{I_0}{2}$ We can use the law of Malus to determine the intensity of the light after passing through the second polarizer. $I = \frac{I_0}{2}~cos^2(45^{\circ}) = \frac{1}{4}\times I_0$ The fraction of the incident light intensity that is transmitted is $\frac{1}{4}$
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