Answer
We can see the graph of $I = I_0~cos^2~\theta$ below.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/719373ea-d530-45b0-ba98-8df2ace332b4/result_image/1535603467.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T013749Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=ed6d3400db193913261e3526e0e896522a398b5f1a9cf20d122d7ff02e4e01a2)
Work Step by Step
We can use Malus' law to sketch the graph of $I$ as a function of $\theta$. Note that $I = I_0~cos^2~\theta$
We can find $I$ for these angles $\theta$:
When $\theta = 0^{\circ}$, $I = I_0~cos^2~0^{\circ} = I_0$
When $\theta = 30^{\circ}$, $I = I_0~cos^2~30^{\circ} = \frac{3I_0}{4}$
When $\theta = 45^{\circ}$, $I = I_0~cos^2~45^{\circ} = \frac{I_0}{2}$
When $\theta = 60^{\circ}$, $I = I_0~cos^2~60^{\circ} = \frac{I_0}{4}$
When $\theta = 90^{\circ}$, $I = I_0~cos^2~90^{\circ} = 0$
When $\theta = 120^{\circ}$, $I = I_0~cos^2~120^{\circ} = \frac{I_0}{4}$
When $\theta = 135^{\circ}$, $I = I_0~cos^2~135^{\circ} = \frac{I_0}{2}$
When $\theta = 150^{\circ}$, $I = I_0~cos^2~150^{\circ} = \frac{3I_0}{4}$
When $\theta = 180^{\circ}$, $I = I_0~cos^2~180^{\circ} = I_0$
When $\theta = 210^{\circ}$, $I = I_0~cos^2~210^{\circ} = \frac{3I_0}{4}$
When $\theta = 225^{\circ}$, $I = I_0~cos^2~225^{\circ} = \frac{I_0}{2}$
When $\theta = 240^{\circ}$, $I = I_0~cos^2~240^{\circ} = \frac{I_0}{4}$
When $\theta = 270^{\circ}$, $I = I_0~cos^2~270^{\circ} = 0$
When $\theta = 300^{\circ}$, $I = I_0~cos^2~300^{\circ} = \frac{I_0}{4}$
When $\theta = 315^{\circ}$, $I = I_0~cos^2~315^{\circ} = \frac{I_0}{2}$
When $\theta = 330^{\circ}$, $I = I_0~cos^2~330^{\circ} = \frac{3I_0}{4}$
When $\theta = 360^{\circ}$, $I = I_0~cos^2~360^{\circ} = I_0$
We can see the graph of $I = I_0~cos^2~\theta$ below.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/719373ea-d530-45b0-ba98-8df2ace332b4/steps_image/small_1535603467.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T013749Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=0d4b722f431bf71ca9a6e4f6051e03cc27d82a208f19a53e280d9ddf449d1f03)