College Physics (4th Edition)

(a) $\Phi = 0.090~Wb$ (b) $\Phi = 0.16~Wb$ (c) The current through the top side of the loop flows in the negative z direction.
(a) We can find the magnetic flux: $\Phi = B~A~cos~\theta$ $\Phi = (0.32~T)~(0.75~m)(0.75~m)~cos~60^{\circ}$ $\Phi = 0.090~Wb$ (b) We can find the magnetic flux: $\Phi = B~A~cos~\theta$ $\Phi = (0.32~T)~(0.75~m)(0.75~m)~cos~30^{\circ}$ $\Phi = 0.16~Wb$ (c) The magnetic flux in the positive x direction is increasing, thus, the induced current will produce a magnetic field with a component in the negative x direction. By the right hand rule, this current flows around the square loop such that the current through the top side of the loop flows in the negative z direction.