Answer
$\Phi = 5.2\times 10^{-5}~Wb$
Work Step by Step
We can find the magnetic flux:
$\Phi = B~A~cos~\theta$
$\Phi = (0.044\times 10^{-3}~T)~(1.3~m)(1.0~m)~cos~25^{\circ}$
$\Phi = 5.2\times 10^{-5}~Wb$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 20 - Problems - Page 794: 12
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