College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 20 - Problems - Page 794: 12


$\Phi = 5.2\times 10^{-5}~Wb$

Work Step by Step

We can find the magnetic flux: $\Phi = B~A~cos~\theta$ $\Phi = (0.044\times 10^{-3}~T)~(1.3~m)(1.0~m)~cos~25^{\circ}$ $\Phi = 5.2\times 10^{-5}~Wb$
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