## College Physics (4th Edition)

Since the foot is in equilibrium, the sum of the three forces equals zero. We can find the force $F_T$ exerted on the foot by the tibia: $F_N+F_A-F_T = 0$ $F_T = F_N+F_A$ $F_T = (750~N)+(2230~N)$ $F_T = 2980~N$ The force exerted on the foot by the tibia is 2980 N.