College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems: 32

Answer

The force exerted on the foot by the tibia is 2980 N

Work Step by Step

Since the foot is in equilibrium, the sum of the three forces equals zero. We can find the force $F_T$ exerted on the foot by the tibia: $F_N+F_A-F_T = 0$ $F_T = F_N+F_A$ $F_T = (750~N)+(2230~N)$ $F_T = 2980~N$ The force exerted on the foot by the tibia is 2980 N.
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