College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems: 22

Answer

The x-component is 17.3 m and the y-component is 10.0 m

Work Step by Step

We can find the magnitude of the x-component which is in the negative x-direction: $\frac{x}{20.0~m} = sin(60.0^{\circ})$ $x = (20.0~m)~sin(60.0^{\circ})$ $x = 17.3~m$ We can find the magnitude of the y-component which is in the positive y-direction: $\frac{y}{20.0~m} = cos(60.0^{\circ})$ $y = (20.0~m)~cos(60.0^{\circ})$ $y = 10.0~m$ The x-component is 17.3 m and the y-component is 10.0 m.
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