## College Physics (4th Edition)

(a) $Q = 5.00~C$ (b) $3.125\times 10^{19}$ electrons move through the cross-section.
(a) We can find the total charge that flows through a cross-section in 10.0 seconds: $Q = A \times t$ $Q = (0.500~A)(10.0~s)$ $Q = (0.500~C/s)(10.0~s)$ $Q = 5.00~C$ (b) We can find the number of electrons: $\frac{5.00~C}{1.6\times 10^{-19}~C} = 3.125\times 10^{19}$ $3.125\times 10^{19}$ electrons move through the cross-section.