Answer
(a) $Q = 5.00~C$
(b) $3.125\times 10^{19}$ electrons move through the cross-section.
Work Step by Step
(a) We can find the total charge that flows through a cross-section in 10.0 seconds:
$Q = A \times t$
$Q = (0.500~A)(10.0~s)$
$Q = (0.500~C/s)(10.0~s)$
$Q = 5.00~C$
(b) We can find the number of electrons:
$\frac{5.00~C}{1.6\times 10^{-19}~C} = 3.125\times 10^{19}$
$3.125\times 10^{19}$ electrons move through the cross-section.
