## College Physics (4th Edition)

(a) $Q = 648,000~C$ (b) $E = 7.78\times 10^6~J$ (c) It takes 54.5 hours to drain the battery.
(a) We can calculate the charge: $Q = 180.0~A\cdot h$ $Q = (180.0~C/s)(3600~s)$ $Q = 648,000~C$ (b) We can calculate the energy: $E = V~Q$ $E = (12.0~V)(648,000~C)$ $E = 7.78\times 10^6~J$ (c) We can find the time it takes to drain the battery: $t = \frac{180~A\cdot h}{3.30~A} = 54.5~hours$ It takes 54.5 hours to drain the battery.