## College Physics (4th Edition)

(a) $Q = 264~C$ (b) $E = 3170~J$
(a) We can find the charge: $Q = A~t$ $Q = (220.0~A)(1.20~s)$ $Q = 264~C$ (b) We can find the energy supplied by the battery: $E = V~Q$ $E = (12.0~V)(264~C)$ $E = 3170~J$