## College Physics (4th Edition)

The electric potential energy released is $1.25\times 10^9~J$
We can find the energy that is released: $U = \frac{1}{2}~Q~V$ $U = \frac{1}{2}~(-25.0~C)(-1.00\times 10^8~V)$ $U = 1.25\times 10^9~J$ The electric potential energy released is $1.25\times 10^9~J$.