College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 657: 86


$U = 2.4\times 10^{-6}~J$

Work Step by Step

We can find the energy stored in the capacitor: $U = \frac{1}{2}~Q~V$ $U = \frac{1}{2}~(0.020\times 10^{-6}~C)(240~V)$ $U = 2.4\times 10^{-6}~J$
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