College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 657: 83


(a) $Q = 1.8\times 10^{-8}~C$ (b) $U = 1.35\times 10^{-6}~J$

Work Step by Step

(a) We can find the charge on the capacitor: $Q = C~\Delta V$ $Q = (\frac{\epsilon_0~A}{d})~\Delta V$ $Q = (\frac{(8.854\times 10^{-12}~F/m)~(0.10~m)^2}{0.75\times 10^{-3}~m})~(150~V)$ $Q = 1.8\times 10^{-8}~C$ (b) We can find the energy stored in the capacitor: $U = \frac{1}{2}~Q~V$ $U = \frac{1}{2}~(1.8\times 10^{-8}~C)(150~V)$ $U = 1.35\times 10^{-6}~J$
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