College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 654: 35


(a) The point Y is at a higher potential. (b) $V_y-V_x = 5.0~J/C$

Work Step by Step

(a) We can write an expression for the work done by the electric field: $W = E~d~q$ $W = -\Delta V~q$ Since the electron's charge is negative and the work is positive, the value of $\Delta V$ must be positive. Therefore, $V_y-V_x$ is positive, so the point Y is at a higher potential. (b) We can find $V_y-V_x$, which is equal to $\Delta V$: $W = -\Delta V~q$ $\Delta V = -\frac{W}{q}$ $\Delta V = -\frac{8.0\times 10^{-19}~J}{-1.6\times 10^{-19}~C}$ $V_y-V_x = 5.0~J/C$
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