College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 654: 43


$\Delta K = 9.6\times 10^{-14}~J$

Work Step by Step

We can use conservation of energy to find the change in kinetic energy: $K_2+U_2 = K_1+U_1$ $K_2- K_1 = U_1 - U_2$ $K_2- K_1 = V_1~q - V_2~q$ $K_2- K_1 = (V_1 - V_2)~q$ $\Delta K = (500.0~kV-200.0~kV)(2)(1.6\times 10^{-19}~C)$ $\Delta K = 9.6\times 10^{-14}~J$
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