College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 17 - Problems - Page 653: 34


(a) $F = 1.0\times 10^{-6}~N$ (b) $W = 2.5\times 10^{-7}~J$ (c) $\Delta V = 60~J/C$

Work Step by Step

(a) We can find the force exerted on the particle: $F = E~q$ $F = (240~N/C)(4.2\times 10^{-9}~C)$ $F = 1.0\times 10^{-6}~N$ (b) We can find the work done by the electric field: $W = F~d$ $W = (1.0\times 10^{-6}~N)(0.25~m)$ $W = 2.5\times 10^{-7}~J$ (c) We can find the potential difference: $\Delta V = E~d$ $\Delta V = (240~N/C)(0.25~m)$ $\Delta V = 60~J/C$
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