College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 16 - Problems - Page 613: 7


$q_A = \frac{Q}{4}$ $q_B = 0$ $q_C = \frac{Q}{4}$

Work Step by Step

Since the spheres are identical, when two spheres are brought in contact, the charges will arrange themselves so that both spheres have the same net charge. Initially: $q_A = Q$ $q_B = 0$ $q_C = 0$ After sphere A touches sphere B: $q_A = \frac{Q}{2}$ $q_B = \frac{Q}{2}$ $q_C = 0$ Since sphere C is grounded when it is touching sphere B, electrons will flow through the ground connection so that the net charge on sphere B and the net charge on sphere C are both zero. After sphere B touches sphere C: $q_A = \frac{Q}{2}$ $q_B = 0$ $q_C = 0$ After sphere C touches sphere A: $q_A = \frac{Q}{4}$ $q_B = 0$ $q_C = \frac{Q}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.