College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 16 - Problems - Page 613: 4

Answer

The new charge of the sphere is $~2.7~nC$ The new charge of the rod is $~-4.7~nC$

Work Step by Step

We can assume that the electrons are transferred from the negatively charged rod to the positively charged sphere. We can find the charge of $8.2\times 10^9$ electrons: $q = (8.2\times 10^9)(-1.6\times 10^{-19}~C)$ $q = -1.3\times 10^{-9}~C$ $q = -1.3~nC$ The new charge of the sphere is $4.0~nC-1.3~nC$ which is $2.7~nC$ The new charge of the rod is $-6.0~nC-(-1.3~nC)$ which is $-4.7~nC$
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