## College Physics (4th Edition)

The total translational kinetic energy is $151.5~J$
The total translational kinetic energy is the number of molecules $N$ multiplied by the average translational kinetic energy of the molecules $\overline{KE}$. We can find the total translational kinetic energy: $N\times~\overline{KE} = \frac{3}{2}~NkT$ $N\times~\overline{KE} = \frac{3}{2}~PV$ $N\times~\overline{KE} = \frac{3}{2}~(1.01\times 10^5~Pa)(0.00100~m^3)$ $N\times~\overline{KE} = 151.5~J$ The total translational kinetic energy is $151.5~J$