## College Physics (4th Edition)

We can find an expression for the original pressure: $P_1V = nRT_1$ $P_1 = \frac{nRT_1}{V}$ We can find an expression for the new pressure: $P_2V = nRT_2$ $P_2 = \frac{nRT_2}{V}$ We can divide $P_2$ by $P_1$ to find the new pressure $P_2$: $\frac{P_2}{P_1} = \frac{\frac{nRT_2}{V}}{\frac{nRT_1}{V}}$ $P_2 = \frac{T_2}{T_1}~P_1$ $P_2 = \left(\frac{373~K}{240~K}\right)~P_1$ $P_2 = 1.55~P_1$ The pressure at the higher temperature is multiplied by a factor of 1.55