College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 499: 58


The gas occupies a volume of $0.0224~m^3$

Work Step by Step

We can find the volume: $PV = NkT$ $V = \frac{NkT}{P}$ $V = \frac{(6.022\times 10^{23})(1.38\times 10^{-23}~J/K)(273~K)}{1.013\times 10^5~Pa}$ $V = 0.0224~m^3$ The gas occupies a volume of $0.0224~m^3$
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