College Physics (4th Edition)

The gas occupies a volume of $0.0224~m^3$
We can find the volume: $PV = NkT$ $V = \frac{NkT}{P}$ $V = \frac{(6.022\times 10^{23})(1.38\times 10^{-23}~J/K)(273~K)}{1.013\times 10^5~Pa}$ $V = 0.0224~m^3$ The gas occupies a volume of $0.0224~m^3$