## College Physics (4th Edition)

(a) The oxygen would occupy a volume of $2.56~m^3$ at atmospheric pressure. (b) The cylinder of oxygen will last for $320~minutes$
(a) We can use Boyle's law to find the volume at atmospheric pressure: $P_2~V_2 = P_1~V_1$ $V_2 = \frac{P_1~V_1}{P_2}$ $V_2 = \frac{(15.2\times 10^6~Pa)(0.0170~m^3)}{1.01\times 10^5~Pa}$ $V_2 = 2.56~m^3$ The oxygen would occupy a volume of $2.56~m^3$ at atmospheric pressure. (b) We can convert the volume at atmospheric pressure to units of liters: $2.56~m^3 \times \frac{10^3~L}{1~m^3} = 2.56\times 10^3~L$ We can find the time that the oxygen lasts: $t = \frac{2.56\times 10^3~L}{8.0~L/min} = 320~min$ The cylinder of oxygen will last for $320~minutes$