College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 498: 43


The new temperature of the air is $400^{\circ}C$

Work Step by Step

We can find an expression for the original temperature: $P_i~V_i = nRT_i$ $T_i = \frac{P_i~V_i}{nR}$ We can find the new temperature $T_f$: $P_f~V_f = nRT_f$ $T_f = \frac{P_f~V_f}{nR}$ $T_f = \frac{(20.0~P_i)(0.111~V_i)}{nR}$ $T_f = (20.0)(0.111)\times \frac{P_i~V_i}{nR}$ $T_f = (20.0)(0.111)\times T_i$ $T_f = (20.0)(0.111)\times 303~K$ $T_f = 673~K$ $T_f = 400^{\circ}C$ The new temperature of the air is $400^{\circ}C$.
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