College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 498: 42

Answer

The required fractional change in pressure is $0.021$

Work Step by Step

We can find an expression for the original pressure: $P_1V = nRT_1$ $P_1 = \frac{nRT_1}{V}$ We can find an expression for the new pressure: $P_2V = nRT_2$ $P_2 = \frac{nRT_2}{V}$ We can divide $P_2$ by $P_1$: $\frac{P_2}{P_1} = \frac{\frac{nRT_2}{V}}{\frac{nRT_2}{V}}$ $\frac{P_2}{P_1} = \frac{T_2}{T_1}$ $\frac{P_2}{P_1} = \frac{297~K}{291~K}$ $\frac{P_2}{P_1} = 1.021$ The required fractional change in pressure is $0.021$
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