College Physics (4th Edition)

The amount of water that overflows is $16.2~cm^3$
We can find the original volume: $V = (75.0~cm^2)(20.0~cm) = 1500~cm^2$ We can find the change in volume of the brass container due to the increase in temperature: $\Delta V = \beta~\Delta T~V$ $\Delta V = (56\times 10^{-6}~K^{-1})(70.0~K)(1500~cm^3)$ $\Delta V = 5.88~cm^3$ We can find the change in volume of the water due to the increase in temperature: $\Delta V = \beta~\Delta T~V$ $\Delta V = (210\times 10^{-6}~K^{-1})(70.0~K)(1500~cm^3)$ $\Delta V = 22.05~cm^3$ The amount of water that overflows is $22.05~cm^3-5.88~cm^3$ which is $16.2~cm^3$