College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 497: 15

Answer

The length of the bridge might change by $1.28~m$ during the year.

Work Step by Step

We can convert the two temperatures to $^{\circ}C$: $C_1 = \frac{5}{9}(F-32)$ $C_1 = \frac{5}{9}(-15-32)$ $C_1 = -26.1^{\circ}C$ $C_2 = \frac{5}{9}(F-32)$ $C_2 = \frac{5}{9}(105-32)$ $C_2 = 40.6^{\circ}C$ The change in temperature is $66.7^{\circ}C$ We can find the increase in length of the steel bridge when it is heated from $-26.1^{\circ}C$ to $40.6^{\circ}C$: $\Delta L = \alpha~\Delta T~L$ $\Delta L = (12\times 10^{-6}~K^{-1})(66.7~K)~(1600~m)$ $\Delta L = 1.28~m$ The length of the bridge might change by $1.28~m$ during the year.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.