## College Physics (4th Edition)

(a) The change in volume of the metallic dental filling is $-0.053~mm^3$ (b) The change in volume of the cavity is $-0.021~mm^3$
(a) We can find the change in volume due to the decrease in temperature: $\Delta V = \beta~\Delta T~V$ $\Delta V = (42\times 10^{-6}~K^{-1})(-42~K)(30~mm^3)$ $\Delta V = -0.053~mm^3$ The change in volume of the metallic dental filling is $-0.053~mm^3$ (b) We can find the change in volume due to the decrease in temperature: $\Delta V = \beta~\Delta T~V$ $\Delta V = (17\times 10^{-6}~K^{-1})(-42~K)(30~mm^3)$ $\Delta V = -0.021~mm^3$ The change in volume of the cavity is $-0.021~mm^3$