College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Multiple-Choice Questions - Page 495: 6


The correct answer is: (a) $V_0$

Work Step by Step

We can find an expression for the volume: $PV = nRT$ $V = \frac{nRT}{P}$ We can write the expression for the original volume: $V_0 = \frac{nRT_0}{P_0}$ We can find the new volume: $V' = \frac{nR(3T_0)}{(3P_0)}$ $V' = \frac{nRT_0}{P_0}$ $V' = V_0$ The correct answer is: (a) $V_0$
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