## College Physics (4th Edition)

We can write an expression for the average kinetic energy: $\overline{KE} = \frac{3}{2}~\frac{PV}{N}$ $\overline{KE} = \frac{3}{2}~kT$ We can see that the absolute temperature $T$ of an ideal gas is directly proportional to the average translational kinetic energy of the gas. The correct answer is: (c) the average translational kinetic energy of the gas.