College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 19: 3


The radius increases by 7.70%.

Work Step by Step

$V_0 = 4\pi r_0^2$ After taking the balloon inside the house, the new volume $V$ is $1.160\times V_0$. $V = 1.160\times V_0$ $4\pi r^2 = 1.160\times 4 \pi r_0^2$ $r^2 = 1.160 \times r_0^2$ $r = \sqrt{1.160 \times r_0^2}$ $r = 1.0770 ~r_0$ The radius increases by a factor of 1.0770 which is an increase of $0.0770 \times 100\%$ which is equal to 7.70%. The radius increases by 7.70%.
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