College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems: 17

Answer

(a) $= 1.29 \times 10^8~kg$ (b) $= 1.3 \times 10^8 ~m/s$

Work Step by Step

(a) $3.783 \times 10^6~kg + 1.25 \times 10^8 ~kg$ $= 0.03783 \times 10^8~kg + 1.25 \times 10^8 ~kg$ $ = 1.28783 \times 10^8~kg$ $= 1.29 \times 10^8~kg$ (b) $(3.783\times 10^6~m) \div (3.0\times 10^{-2}~s)$ $ = 1.261 \times 10^8 ~m/s$ $= 1.3 \times 10^8 ~m/s$
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