College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems: 13

Answer

The cross-sectional area of the artery increases by a factor of 4.0

Work Step by Step

The original area of the artery is $A_0 = \pi r^2$. The new radius is $2.0~r$. We can find the ratio of the new area $A$ to the original area $A_0$. $ratio = \frac{A}{A_0} = \frac{\pi (2.0r)^2}{\pi r^2} = \frac{4.0 ~\pi r^2}{\pi r^2} = 4.0$ The cross-sectional area of the artery increases by a factor of 4.0.
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