Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 131: 40

Answer

Please see the work below.

Work Step by Step

According to law of conservation of energy $\frac{1}{2}mv^2=mgdsin(\theta)$ This simplifies to: $d=\frac{v^2}{2gsin(\theta)}$ We plug in the known values to obtain: $d=\frac{(\frac{110}{3.6})^2}{(2)(9.8)sin(30)}$ $d=95m$
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