Answer
Please see the work below.
Work Step by Step
According to law of conservation of energy
$\frac{1}{2}mv^2=mgdsin(\theta)$
This simplifies to:
$d=\frac{v^2}{2gsin(\theta)}$
We plug in the known values to obtain:
$d=\frac{(\frac{110}{3.6})^2}{(2)(9.8)sin(30)}$
$d=95m$
