Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 131: 35

Answer

Please see the work below.

Work Step by Step

We know that $Potential \space energy=mgh$ We plug in the known values to obtain: $Potential \space energy= 2.1\times 10^{10}\times 9.8\times 214$ $Potential \space energy=4.404\times 10^{13}J$ (b) We know that $P=\frac{W}{T}$ This can be rearranged as: $T=\frac{W}{P}$ We plug in the known values to obtain: $T=\frac{4.404\times 10^{13}}{1.08\times 10^9}$ $T=40778.88s=11.32 Hours$
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